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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 22:51:27
|
is the plus (x^2 + i) correct?
| 1 | 0 | 220,517,274,845,577,200 |
ramonov
|
0921
|
ℝamonov
| false |
|||||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 22:51:35
|
that says x^2+1
| 0 | 1 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 22:51:53
|
i^2+1=0
| 0 | 1 | null | null | null | null | null |
|||||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 22:53:29
|
it might help to remember the conjugate root theorem to understand where i got x^2+1 from. i being a zero implies -i being a zero, implies (x-i)(x+i)=x^2+1 being a factor.
| 0 | 1 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 22:55:00
|
I'm not accustomed with complex numbers yet, but about the exercise I'm sure it's like that
| 1 | 0 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 22:56:10
|
I couldn't interpret the graph in regards to division by 6
| 1 | 0 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 22:56:37
|
ah, it states = 27
| 1 | 0 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 22:57:37
|
It does work if g is meant to be an integer polynomial with those conditions
| 0 | 1 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 22:58:01
|
but in the realm of real polynomials, there are certainly many g st g(0) isn't divisible by 6
| 0 | 1 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 22:58:30
|
when we take out the 0.5 we'd have 54 which is divisible
| 1 | 0 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 22:58:40
|
yes you would.
| 0 | 1 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 23:00:17
|
that doesn't discount the fact that 0.5(x-2)(x-3)^2(x^2+1) is a counterexample
| 0 | 1 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:02:31
|
it wouldn't save the question if I said if we scale the polynomial, we expect to scale the value 6 aswell, no?
| 1 | 0 | 220,517,274,845,577,200 |
ramonov
|
0921
|
ℝamonov
| false |
|||||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:02:55
|
because instead of 0.5 we can use any arbitrary scaling
| 1 | 0 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:03:14
|
so division by whole number would get lost definitely
| 1 | 0 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:03:25
|
or not?
| 1 | 0 | null | null | null | null | null |
|||||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 23:04:07
|
This could be me but I can't really figure out what you're trying to say
| 0 | 1 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 329,749,386,315,956,200 |
Sneaky
|
12/23/2021 23:04:55
|
The simplest way to save the problem would be to say g has to be an integer polynomial, but I don't really like doing the "guess what the question is meant to say" thing
| 0 | 1 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:06:21
|
I had a fallacy
| 1 | 0 | null | null | null | null | null |
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205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:08:25
|
well then
| 1 | 0 | null | null | null | null | null |
|||||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:08:49
|
seems like a dead end to me with having your counterexample, so I'll have to ask my tutor
| 1 | 0 | null | null | null | null | null |
|||||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:09:06
|
I thank you for your help @Sneaky
| 1 | 0 | null | null | null | null | null |
|||||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
| 332,164,791,143,759,900 |
tarık b.
|
12/23/2021 23:09:36
|
.close
| 1 | 0 | 320,090,412,012,404,740 |
Kubra
|
2061
|
Kubra
| false |
|||||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 760,358,915,925,475,300 |
Intrexa
|
01/31/2022 21:14:22
|
Hey, I'm stumped on lim(x->pi/2) for (cos^2 x)/(1-sin x). I've tried messing around with substituting identities, either I'm off base, or not seeing it, or w/e
| 1 | 0 | null | null | null | null | null |
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205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 760,358,915,925,475,300 |
Intrexa
|
01/31/2022 21:14:49
|
Any help for the answer is good, any insight into the intuition as to why it's the answer is what I'm looking for
| 1 | 0 | null | null | null | null | null |
|||||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 186,109,587,366,215,680 |
Omegabet_
|
01/31/2022 21:15:18
|
Hint: Pythagorean identity
| 0 | 1 | null | null | null | null | null |
|||||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 760,358,915,925,475,300 |
Intrexa
|
01/31/2022 21:16:05
|
I tried throwing that in, (cos^2 x)/(cos^2 x + sin^2 x - sin x), but I'm stumped on that front
| 1 | 0 | null | null | null | null | null |
|||||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 186,109,587,366,215,680 |
Omegabet_
|
01/31/2022 21:16:18
|
$\cos^2(x)=1-\sin^2(x)$
| 0 | 1 | null | null | null | null | null |
|||||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 510,789,298,321,096,700 |
TeXit
|
01/31/2022 21:16:20
|
**Mosh**
|
186109587366215691.png
| 0 | 1 | null | null | null | null | null |
||||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 760,358,915,925,475,300 |
Intrexa
|
01/31/2022 21:16:48
|
ahhh yeah
| 1 | 0 | 320,090,412,012,404,740 |
Kubra
|
2061
|
Kubra
| false |
|||||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 308,723,121,744,248,800 |
noot noot
|
01/31/2022 21:17:54
|
thanks pythagoras
| 0 | 1 | null | null | null | null | null |
|||||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
| 760,358,915,925,475,300 |
Intrexa
|
01/31/2022 21:17:57
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 760,358,915,925,475,300 |
Intrexa
|
01/31/2022 21:18:02
|
thx all
| 1 | 0 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:11:26
|
how do i understand what {u, v} is because i set up the equations but don't know how they are equal to {u, v}
|
unknown.png
| 0 | 1 | null | null | null | null | null |
||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:12:24
|
wdym?
| 0 | 1 | 320,090,412,012,404,740 |
Kubra
|
2061
|
Kubra
| false |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:12:53
|
i don't know how to set up the system of equations
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:14:35
|
ok so lets do the first one together
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:15:11
|
we want to see if there are numbers (scalars) a,b such that a*[1,-2] + b * [-2,5] = [-2,5] correct?
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:15:30
|
yeah
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:15:58
|
ok, so then we simplify the LHS
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:16:14
|
we have [a-2a] + [-2b+5b] = [-2,5]
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:16:26
|
which implies that a-2b = -2, -2a+5b = 5
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:16:28
|
with me so far?
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:16:51
|
we then solve this system of linear equations
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:16:58
|
(which im assuming you know how to do)
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:18:16
|
ohh i think i understand how you made the system
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:18:20
|
yup
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:18:35
|
because [a,b] + [c,d] = [a+c, b+d]
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:19:41
|
ok then you can prove its a linear combination by finding a and b?
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:33:01
|
is the vector a linear combination of {u,v}? i solved the system of equations and got a=0 and b=1
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:33:15
|
great
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:33:20
|
yup
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:34:22
|
since the A vector is similar to C is it also a correct linear combination?
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:34:47
|
what do you mean "similar"
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:34:58
|
but to answer your question, you did prove that it is a linear combination
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:35:34
|
they are both equal to the given vectors u and v
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:35:56
|
i dont see what you mean
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:36:01
|
plz give an example
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:36:36
|
unknown.png
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:36:36
|
unknown.png
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:36:36
|
unknown.png
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:37:12
|
correct
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:38:33
|
are those the only linear combinations in the list?
|
unknown.png
| 0 | 1 | null | null | null | null | null |
||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:38:44
|
that is for you to figure out
| 0 | 1 | null | null | null | null | null |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:38:47
|
repeat the process
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:38:48
|
😉
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:39:21
|
is it only a linear comb if there's a solution to the system
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:39:41
|
well yes
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:39:47
|
like if u = v = [0,0]
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:40:07
|
then if answer H is "The vector [1,1] is a lin. comb. of {u,v}
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:40:09
|
it is false
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 714,316,705,303,625,900 |
Invictus
|
01/31/2022 22:40:11
|
get it?
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:40:52
|
ohh ok then this probably means all real vectors are linear combinations
| 0 | 1 | null | null | null | null | null |
|||||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
| 315,292,317,315,629,060 |
Ptolemy
|
01/31/2022 22:48:17
|
@Invictus is choosing every vector that's not a multiple of u1 and u2 a good strategy to tell what's not in the span?
|
unknown.png
| 0 | 1 | null | null | null | null | null |
||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 551,269,104,800,104,450 |
EndTimes
|
01/31/2022 23:16:13
|
the one sheeted hyperboloid has cartesian eqn:
| 1 | 0 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 551,269,104,800,104,450 |
EndTimes
|
01/31/2022 23:16:40
|
x^2/a^2 + y^2/b^2 - z^2/c^2 = 1
| 1 | 0 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 551,269,104,800,104,450 |
EndTimes
|
01/31/2022 23:16:51
|
what do a b c represent here
| 1 | 0 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 551,269,104,800,104,450 |
EndTimes
|
01/31/2022 23:17:05
|
geometrically speaking!
| 1 | 0 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 551,269,104,800,104,450 |
EndTimes
|
01/31/2022 23:17:09
|
lol
| 1 | 0 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 551,269,104,800,104,450 |
EndTimes
|
01/31/2022 23:19:12
|
@Helpers
| 1 | 0 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 551,269,104,800,104,450 |
EndTimes
|
01/31/2022 23:44:22
|
@Helpers
| 1 | 0 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 569,167,697,925,898,240 |
Camilleone
|
02/01/2022 00:24:04
|
geometrically they're the principal semi-axes
| 0 | 1 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 183,668,144,404,037,630 |
Ann
|
02/01/2022 00:51:08
|
@EndTimes the 'unit' hyperboloid of one sheet has equation x^2 + y^2 - z^2 = 1
| 0 | 1 | null | null | null | null | null |
|||||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
| 183,668,144,404,037,630 |
Ann
|
02/01/2022 00:51:22
|
dilating it by a, b and c along the x, y and z axes gives yours
| 0 | 1 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:27:44
|
Hey Guys, I have a problem with the calculation
I have to get x1, x2 and x3 and it uses ZZ7, so Im not sure how to solve it, I used the gauss algorithm already, but I dont know whether its correct or not:
|
unknown.png
| 1 | 0 | null | null | null | null | null |
||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:27:44
|
Hey Guys, I have a problem with the calculation
I have to get x1, x2 and x3 and it uses ZZ7, so Im not sure how to solve it, I used the gauss algorithm already, but I dont know whether its correct or not:
|
unknown.png
| 1 | 0 | null | null | null | null | null |
||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:28:17
|
Also, I got out for x1 = 1.5, for x2 =0 and for x3 = -1
| 1 | 0 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:29:34
|
Or was I wrong to use the Gauss Algorithm here?
| 1 | 0 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 510,789,298,321,096,700 |
TeXit
|
02/01/2022 02:32:50
|
**Ansh**
|
706934233012371577.png
| 0 | 1 | null | null | null | null | null |
||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 706,934,233,012,371,600 |
Ansh_
|
02/01/2022 02:33:17
|
hmm the Z7
| 0 | 1 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:33:45
|
Well, I was a bit confused because I'm limited to the body ZZ7 right? This one
|
unknown.png
| 1 | 0 | null | null | null | null | null |
||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:34:16
|
Or maybe its called a "field" in english
| 1 | 0 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:34:35
|
So the number only goes from 0 up to 6
| 1 | 0 | 320,090,412,012,404,740 |
Kubra
|
2061
|
Kubra
| false |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:34:42
|
(I think)
| 1 | 0 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 02:41:53
|
yup
| 1 | 0 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 03:42:42
|
Well, if no one knows the answer to those, I would need help with something else as well
| 1 | 0 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 03:43:18
|
Give the generator polynomials and the corresponding generator matrices and control polynomials of all 6-digit cyclic codes with 3 control digits over Z5.
| 1 | 0 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 236,549,522,178,834,430 |
Revogue
|
02/01/2022 03:43:43
|
And I'm absolutely confused on how I can do that
| 1 | 0 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 915,938,343,857,037,300 |
Quincy
|
02/01/2022 04:05:27
|
If u know inverse matrix, then just multiply inverse of the 3*3 matrix to both the sides. The LHS become only x1,x2,x3 and RHS will be inv(3*3) matrix * (1,3,1) matrix
| 0 | 1 | null | null | null | null | null |
|||||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
| 595,185,421,743,554,600 |
Sepdron
|
02/01/2022 04:27:27
|
i think i know how to do it, i think it's like gauss algorithm but instead of dividing, you multiply it by its multiplicative inverse in the finite field
i think it helps if you make the multiplication table for the finite field first
| 0 | 1 | null | null | null | null | null |
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