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|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 03:49:30
|
no yeah I still can't get CDG and CDH
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 03:50:02
|
@Ansh_
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 03:51:47
|
mhmm, the hint now is to drop another perpendicular from D to AB this time and you'll be done
| 0 | 1 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 03:52:40
|
right
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 03:53:29
|
there you go
|
unknown.png
| 0 | 1 | null | null | null | null | null |
||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 03:53:48
|
prove that DE = DK = DF
| 0 | 1 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 03:55:32
|
since, DE = DF now, and DC = DC, and both are right triangles.. DEC is congruent to triangle DFC and you're done
| 0 | 1 | null | null | null | null | null |
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205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:03:00
|
right I got it
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:03:01
|
thank you
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:03:15
|
I feel very dumb that I had this much trouble with that problem but now I am done
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 04:05:45
|
Wait @Gamma is an Algebraic Number
| 0 | 1 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:05:52
|
hm?
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 04:07:55
|
For the actual solution, tbh, you only need to show:
1) ADK congruent to AEK => DK = DE
2) DKB congruent to DFB => DK = DF
=> DE = DF
3) DE = DF, DC = DC, angle DFC = angle DEC = 90° => DFC congruent to DEC [RHS congruency]
Hence, angle DCF = DCE => DC is angle bisector of ACB
therefore, angle bisectors of a triangle are concurrent
| 0 | 1 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:08:07
|
yeah I saw
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 04:08:17
|
[the figuring the angles part I said was only for you to sense the DK = DE = DF part on your own]
| 0 | 1 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:08:26
|
yeah yeah I realized
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 04:08:27
|
👍
| 0 | 1 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:08:47
|
probably would have thought of the third perpendicular thing if I wasn't tired on account of it being 4am
| 1 | 0 | 457,986,659,900,719,100 |
Zuki
|
0133
|
Zuki
| false |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 706,934,233,012,371,600 |
Ansh_
|
01/31/2022 04:08:56
|
mhmm
| 0 | 1 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:09:18
|
I feel somewhat embarrassed that these problems gave me this much trouble
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:10:02
|
like this isn't for highschool geo, it's for an undergrad geometry course that's starting with a review of highschool geo
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:10:24
|
yet I still am failing at math I should have learned 4+ years ago
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:10:39
|
I guess my actual highschool geometry class was shit to be fair
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:12:11
|
anyways, thank you very much for the help
| 1 | 0 | null | null | null | null | null |
|||||
205,792 |
help-1
|
324056081625457eac341c77ef88f9b2
| 381,174,875,215,364,100 |
Gamma is an Algebraic Number
|
01/31/2022 04:12:11
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
205,793 |
help-1
|
bbd05ac504164b63b9abc563d0bd2a2d
| 654,259,766,192,898,000 |
jae🐇
|
01/31/2022 04:18:06
|
could I get help with this
| 1 | 0 | null | null | null | null | null |
|||||
205,793 |
help-1
|
bbd05ac504164b63b9abc563d0bd2a2d
| 654,259,766,192,898,000 |
jae🐇
|
01/31/2022 04:18:08
|
unknown.png
| 1 | 0 | null | null | null | null | null |
|||||
205,793 |
help-1
|
bbd05ac504164b63b9abc563d0bd2a2d
| 654,259,766,192,898,000 |
jae🐇
|
01/31/2022 04:20:21
|
actually nvm i got it
| 1 | 0 | null | null | null | null | null |
|||||
205,793 |
help-1
|
bbd05ac504164b63b9abc563d0bd2a2d
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/31/2022 04:27:44
|
Feel free to .close
| 0 | 1 | null | null | null | null | null |
|||||
205,793 |
help-1
|
bbd05ac504164b63b9abc563d0bd2a2d
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/31/2022 04:27:52
|
Then
| 0 | 1 | null | null | null | null | null |
|||||
205,793 |
help-1
|
bbd05ac504164b63b9abc563d0bd2a2d
| 654,259,766,192,898,000 |
jae🐇
|
01/31/2022 04:29:04
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 05:56:38
|
anyone know how to factorise 4k^2 + 16k + 3. I am trying to solve by using splitting the middle term but am not familiar with it. if some one could teach this method it will help a lot (ps ik how to use quadratic equation, just seeking to find a simpler solution)
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 757,890,033,238,671,400 |
Sabertoothed Rat
|
01/31/2022 05:58:38
|
well it's more logical to solve it using quadratic formula if roots aren't rational
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 05:58:51
|
Using the formula is easier
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 05:59:31
|
fair enough
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 05:59:32
|
But, if you want to use splitting the middle term, multiply the coefficient of k^2 with the constant (3 in this case)
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 05:59:43
|
12
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 05:59:59
|
Find 2 factors of 12 which add up to 16
| 0 | 1 | 510,789,298,321,096,700 |
TeXit
|
0796
|
TeXit
| true |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 06:00:20
|
Lol.
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 06:00:34
|
Can you find it?
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:00:37
|
i cant find any?
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 485,903,210,272,391,200 |
dldh06
|
01/31/2022 06:00:45
|
There's tons of videos on factoring. Maybe looking one up would help
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 06:00:46
|
Maybe because the roots are irrational?
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 757,890,033,238,671,400 |
Sabertoothed Rat
|
01/31/2022 06:00:49
|
they'd be irrational
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 06:00:56
|
Use the formula
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:00:57
|
i c
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:01:01
|
aight
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:01:13
|
can u teach with a different formula. one with rational roots
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:01:25
|
splitting the middle term
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 06:01:26
|
Or you could use completing the square
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:01:34
|
not sure how to do this either
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 06:01:45
|
Search up a video
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:01:51
|
fair enough
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 420,244,167,726,333,950 |
kirby your mom
|
01/31/2022 06:01:55
|
Sure
| 0 | 1 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:02:07
|
thanks
| 1 | 0 | null | null | null | null | null |
|||||
205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
| 478,187,837,771,087,900 |
Siddy
|
01/31/2022 06:17:29
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 06:53:02
|
On Archimedes' tombstone there is said to have been an inscription sol showed a cylinder with an inscribed sphere. 2500 years ago Archimedes found that the ratio between the globe volume and the cylinder volume was always 2/3.
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 06:53:15
|
A) show that the ball is 2/3 of the volume of the cylinder
| 1 | 0 | 914,473,169,648,255,000 |
skymoon
|
7322
|
skymoon
| false |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 06:53:24
|
B) it is actually the case that even the sphere area is 2/3 of the area of the cylinder. Show that it is so. Tip: put the measurement on the globe and the cylinder and count your measurements
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 06:57:18
|
Maybe using Cavalieri's principle?
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:00:14
|
Idk
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:03:23
|
Basically, it's a principle as follows:
Suppose two 3d-objects are included between two parallel planes. If the cross-section of two objects on a plane is equal in area, the two objects have the same area.
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:05:29
|
Huh
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:06:04
|
The standard way to do it is to compare a hemisphere of radius r and a cylinder of radius r and height r minus an upside-down cone with the same radius and height.
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:06:29
|
Huh
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:07:35
|
I don't understand
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:07:57
|
This is a graph from wikipedia.
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:07:59
| 0 | 1 | null | null | null | null | null |
||||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:08:14
|
Ok
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:09:48
|
The volume of the cylinder without the cone part should be equal to the volume of the hemisphere.
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:10:31
|
To show that, we take a slice on a plane parallel to the base of the cylinder at an arbitrary height.
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:14:36
|
What
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:17:11
|
What words are you confused at?
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:17:39
|
Hemisphere, perpendicularl, arbitrary
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:19:00
|
1. Hemisphere = half of an sphere
2. sorry, I mean parallel
3. for any h, show that the slice of both objects have an equal area.
| 0 | 1 | 541,081,246,252,531,700 |
nals
|
3582
|
nals
| false |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:19:41
|
Hmm okb
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:19:45
|
But I still don't understand
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:35:07
|
Which part do you still not understand now?
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:37:29
|
How do I answer a and b
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 07:37:59
|
That proof is answering a
| 0 | 1 | 541,081,246,252,531,700 |
nals
|
3582
|
nals
| false |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 07:39:36
|
Ok
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 08:11:55
|
@Helpers
| 1 | 0 | 914,473,169,648,255,000 |
skymoon
|
7322
|
skymoon
| false |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 08:27:16
|
I mean, I showed you how to solve it. Just apply the Cavalieri's principle on that diagram I have given to answer a.
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 09:02:49
|
I never learned that principle
| 1 | 0 | 872,024,354,572,103,700 |
<><><>
|
9772
|
<><><>
| false |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 09:18:51
|
Well, that's not usually taught in schools, because that technique was rendered obsolete with calculus. But if you want to solve it the was Archimedes did, you have to use that principle.
| 0 | 1 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 09:24:08
|
Uhh
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 898,592,085,215,674,500 |
Samat127
|
01/31/2022 09:24:16
|
How do I answer b then
| 1 | 0 | null | null | null | null | null |
|||||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
| 503,047,891,271,680,000 |
BlokirKominfo
|
01/31/2022 09:34:54
|
Honestly, I don't know it yet.
| 0 | 1 | null | null | null | null | null |
|||||
205,796 |
help-1
|
4a42a3ec41b94839841cc05178121aff
| 321,445,119,171,756,000 |
Shuri2060
|
01/31/2022 10:31:50
|
indeed
| 1 | 0 | null | null | null | null | null |
|||||
205,796 |
help-1
|
4a42a3ec41b94839841cc05178121aff
| 321,445,119,171,756,000 |
Shuri2060
|
01/31/2022 10:31:53
|
triangle inequality
| 1 | 0 | null | null | null | null | null |
|||||
205,796 |
help-1
|
4a42a3ec41b94839841cc05178121aff
| 321,445,119,171,756,000 |
Shuri2060
|
01/31/2022 10:32:04
|
look it up
| 1 | 0 | null | null | null | null | null |
|||||
205,796 |
help-1
|
4a42a3ec41b94839841cc05178121aff
| 321,445,119,171,756,000 |
Shuri2060
|
01/31/2022 10:32:20
|
the one side cannot be longer than the sum of the other 2
| 1 | 0 | 914,473,169,648,255,000 |
skymoon
|
7322
|
skymoon
| false |
|||||
205,797 |
help-1
|
7f9e6926fdcd4dc588b7cfa375115b5e
| 852,592,874,754,932,700 |
CoffeePls
|
01/31/2022 10:52:46
|
image0.jpg
| 1 | 0 | null | null | null | null | null |
|||||
205,797 |
help-1
|
7f9e6926fdcd4dc588b7cfa375115b5e
| 852,592,874,754,932,700 |
CoffeePls
|
01/31/2022 10:52:56
|
where does the x disappear to?
| 1 | 0 | 914,473,169,648,255,000 |
skymoon
|
7322
|
skymoon
| false |
|||||
205,797 |
help-1
|
7f9e6926fdcd4dc588b7cfa375115b5e
| 852,592,874,754,932,700 |
CoffeePls
|
01/31/2022 10:54:19
|
o nvm i misread
| 1 | 0 | 872,024,354,572,103,700 |
<><><>
|
9772
|
<><><>
| false |
|||||
205,797 |
help-1
|
7f9e6926fdcd4dc588b7cfa375115b5e
| 852,592,874,754,932,700 |
CoffeePls
|
01/31/2022 10:54:21
|
.close
| 1 | 0 | 872,024,354,572,103,700 |
<><><>
|
9772
|
<><><>
| false |
|||||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
| 366,576,372,203,651,100 |
Xavier
|
12/23/2021 22:11:19
|
Hi I'm looking for help for a graphing issue
| 1 | 0 | 914,473,169,648,255,000 |
skymoon
|
7322
|
skymoon
| false |
|||||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
| 366,576,372,203,651,100 |
Xavier
|
12/23/2021 22:11:40
|
((x/10)^2) + ((y/10)^2) = 1
((x/5)^2) + (((y-5)/x)^2) = 1
|x| + 6 {-3≼x≼3}
(0.5x^2) - 8 {-4≼x4}
| 1 | 0 | null | null | null | null | null |
|||||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
| 366,576,372,203,651,100 |
Xavier
|
12/23/2021 22:11:50
|
on desmos this graphs out a sorta smiley face
| 1 | 0 | null | null | null | null | null |
|||||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
| 366,576,372,203,651,100 |
Xavier
|
12/23/2021 22:12:24
|
I'm trying to make it work in a way that the average Joe can see this, enter it in a graphing calculator and say, damn that's a face
| 1 | 0 | null | null | null | null | null |
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