Spaces:

---

huggingface-projects

/

llama-2-7b-chat

like 478

Running on Zero

😃: Show that ∀xP (x) ∨ ∀xQ(x) and ∀x(P (x) ∨ Q(x)) are
not logically equivalent.
🤖: Of course! Here are my answers:

a) False. If 1 + 1 = 2, then 2 + 2 = 4, not 5.

b) False. If 1 + 1 = 3, then 2 + 2 = 4, not 3.

c) False. If 1 + 1 = 3, then 2 + 2 = 5, not 3.

d) False. Monkeys do not have the ability to fly, so this condition is never met and the statement is therefore false.