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nathan_from_texas
02/01/2022 22:24:28
yes
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nathan_from_texas
02/01/2022 22:24:32
logic and proofs
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Deleted User
02/01/2022 22:24:35
The way I'd start is
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Deleted User
02/01/2022 22:27:10
I'd first probably annotate the paper, see what I know and what I don't know, highlight important concepts. Then move onto dissecting what I know, making sure I still understand it fully, once I do that I'd start breaking the parts I don't understand into smaller problems and research it, repeat for everything I don't understand. Once I understand the proofs I'd rewrite the paper its in entirety making sure everything make sense in my head and on paper. Before I even start explaining what's happening to someone else
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Deleted User
02/01/2022 22:27:31
You can't really explain it without fully understanding t
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Deleted User
02/01/2022 22:28:00
By no means is that an easy paper to read and itll take time
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nathan_from_texas
02/01/2022 22:28:07
precisely.
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nathan_from_texas
02/01/2022 22:28:23
lol no it is not.
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nathan_from_texas
02/01/2022 22:28:51
thank you for your advice. Did you see any concept that i could google and research off the bat?
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nathan_from_texas
02/01/2022 22:29:30
My dad recommended the fourier transformations, but that's all i could pull out
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nathan_from_texas
02/01/2022 22:29:38
well all that he could pull out
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Deleted User
02/01/2022 22:30:15
I just glanced at it but let me double check
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Deleted User
02/01/2022 22:30:55
Are you familiar with ppt sims?
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nathan_from_texas
02/01/2022 22:32:08
no, i am not. Will research in a bit.
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Deleted User
02/01/2022 22:32:42
I'd also try to reach out to a math professor
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nathan_from_texas
02/01/2022 22:33:20
i reached out to my cybersecurity professor on linkedin, but no response. I'll try linking up with other professors to see what's what.
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nathan_from_texas
02/01/2022 22:34:20
thank you for your time, today. You've helped me progress more than you'd think.
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nathan_from_texas
02/01/2022 22:34:29
.close
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:39:27
Problem is asking for the argument of a complex polynomial? I know the argument is arctan=(y/x) where y is the imaginary and x is the real part, but i am wondering why the answer i get is -.7773 vs theirs which is -.2474Pi (they do something to the -.7773 pic of problem follows this fyi
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:40:41
https://cdn.discordapp.c…412/IMG_4385.jpg
IMG_4385.jpg
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:41:43
For the real/imaginary parts i got -62/85 and 61/85 respectively (which would also be x and y respectively)
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:43:16
The confusing part is why they want an answer from -.7774 to -.2474Pi (i.e. radians, degrees, bounds etc.)
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Ansh_
02/01/2022 22:45:18
(5 + 8i)(2 + 9i)/(85) = (10 - 72 + 61i)/(85) = (-62 +61i)/(85) :devastation:
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:50:47
Shouldn’t the i^2 make the - into a +?
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Ansh_
02/01/2022 22:50:57
nvm smh
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:51:49
Np math makes me cry ever since calc 3/diff eq. Linear algebra wasn’t too bad 😅
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Ansh_
02/01/2022 22:52:14
,w pi - arctan 61/62
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:52:16
But I’m more focused on the argument part of the question
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:52:35
Shouldn’t it be 61/-62?
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:53:24
Since 61 is the imaginary part it would be the Y value and -62 is the real part so X?
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:53:51
So why is it Pi-arctan?
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Ansh_
02/01/2022 22:54:36
my reasoning is: because - (-62/85, 61/85) lies in second quad. and argument is angle from +x
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Ansh_
02/01/2022 22:54:49
so it should work that way but apparently not
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:55:09
Cause for my class (not sure which is right though) they get -.7774 = -.2474Pi which is where I’m stuck at, how and why did they convert it to the -.2474
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Ansh_
02/01/2022 22:56:41
for the conversion part, I think they just divided the (.7774) by pi and multiplied with the π, to get -.2474π
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:57:47
Ahhhhh so they left the Pi and the .2474 is just .7774/Pi
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꧁༺【Mr Anthony】༻꧂
02/01/2022 22:58:40
I was wondering if the argument by definition is in Pi increments or if it was arbitrary
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Ansh_
02/01/2022 22:59:52
nope
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Ansh_
02/01/2022 22:59:58
,calc .7774/pi
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52aff7867bde4ea798b8b9848704cfb8
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TeXit
02/01/2022 22:59:58
Result: ``` 0.24745410551928 ```
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Deleted User
12/24/2021 03:10:27
Hi
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Deleted User
12/24/2021 03:10:48
How do we indentify where to cancel out?
https://cdn.discordapp.c…744/IMG_9836.png
IMG_9836.png
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Deleted User
12/24/2021 03:11:13
How did the teacher know how to find the row to cancel
1
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Deleted User
12/24/2021 03:11:22
Is it something to do with the denominator
1
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Deleted User
12/24/2021 03:14:54
Do I have to test out one by one
1
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ramonov
12/24/2021 03:15:15
do you have a better image
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Deleted User
12/24/2021 03:16:31
Ah sorry
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Deleted User
12/24/2021 03:16:43
https://cdn.discordapp.c…872/IMG_9837.png
IMG_9837.png
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Deleted User
12/24/2021 03:22:32
I understand the cancellation is because of them equating to zero
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Deleted User
12/24/2021 03:23:06
But let’s say we have another set of differentiation, how do we know where to cancel if it is so dissimilar?
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ramonov
12/24/2021 03:42:26
the stuff is still too small the read
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King of Kimchi
02/01/2022 23:33:53
I need to solve this equation (image) for t>0 using Laplace transformations. So far my approach has been dividing both sides by (4/t) and then evaluating RHS integral. which leaves me with: d2y/dt2 + 16y = cos (4t). When I take the Laplace transform of both sides, and use algebraic manipulation, I get: Y(s) = s/(s^2 + 16)^2 + 1/(s^2 + 16) I'm not sure of how to proceed, as partial fractions doesn't seem possible. My question is I guess whether 1. are one of my steps wrong? 2. If my steps are correct, how would you proceed from the Y(s) equation?
https://cdn.discordapp.c…5721/unknown.png
unknown.png
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stabulo
02/01/2022 23:41:28
It would seem you need to rewrite each fraction as you have them into a form similar to (27.84) and (27.86).
https://cdn.discordapp.c…0618/unknown.png
unknown.png
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stabulo
02/01/2022 23:44:03
$Y(s) = + \frac{1}{8} \left( \frac{(2)(4)s}{s^2 + 4^2}\right) + \frac{1}{4}\left( \frac{4}{s^2 + 4^2} \right)$.
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TeXit
02/01/2022 23:44:43
**stabulo**
https://cdn.discordapp.c…303944224768.png
234339303944224768.png
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King of Kimchi
02/01/2022 23:46:57
the first fraction denominator is (s^2 + 16)^2, would that mean it goes into the format of 27.86?
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King of Kimchi
02/01/2022 23:48:10
ohh okay, I think it just clicked, with how you approached the transformation.
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stabulo
02/01/2022 23:48:13
Yes. It just doesn't quite match with a = 4. You effectively need to divide by 1/(2a) to get that form which is why 1/8 is outside the left terms parenthesis.
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King of Kimchi
02/01/2022 23:48:22
Yep, thanks so much! ❤️
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stabulo
02/01/2022 23:48:43
I'm studying this too at the moment so it was a nice opportunity for me.
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King of Kimchi
02/01/2022 23:49:19
.close
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Deleted User
02/02/2022 00:38:16
.close
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doggy
02/02/2022 00:42:47
could someone help
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doggy
02/02/2022 00:43:24
Consider a 60kg student on a slide as shown in the diagram below A) determine their speed at the bottom of the slide in the absence of friction
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KurtDee
02/02/2022 00:43:58
What class is this
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doggy
02/02/2022 00:44:21
https://cdn.discordapp.c…3745/unknown.png
unknown.png
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doggy
02/02/2022 00:44:25
physics
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KurtDee
02/02/2022 00:44:35
Physics 1?
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doggy
02/02/2022 00:44:40
physics 11
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KurtDee
02/02/2022 00:44:45
So many
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f0d566dc2d184b829dd03a9e306eea74
456,226,577,798,135,800
Deleted User
02/02/2022 00:45:00
discord.gg/physics
1
0
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help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:45:02
intro to energy
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935,988,910,025,232,400
Taltost
8448
Taltost
false
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help-1
f0d566dc2d184b829dd03a9e306eea74
193,942,262,336,454,660
KurtDee
02/02/2022 00:45:07
So there’s like 5 major equations for classical physics
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help-1
f0d566dc2d184b829dd03a9e306eea74
193,942,262,336,454,660
KurtDee
02/02/2022 00:45:26
The one you care about here is acceleration due to gravity
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205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:45:41
how do we find it
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help-1
f0d566dc2d184b829dd03a9e306eea74
193,942,262,336,454,660
KurtDee
02/02/2022 00:45:45
Find what
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935,988,910,025,232,400
Taltost
8448
Taltost
false
205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:45:51
accleration
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help-1
f0d566dc2d184b829dd03a9e306eea74
550,652,464,429,400,060
ABHAS
02/02/2022 00:45:57
Conserve the energy
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help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:45:58
i only got 4 formuls and none of them have a
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help-1
f0d566dc2d184b829dd03a9e306eea74
550,652,464,429,400,060
ABHAS
02/02/2022 00:46:00
WET
0
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935,988,910,025,232,400
Taltost
8448
Taltost
false
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help-1
f0d566dc2d184b829dd03a9e306eea74
649,984,702,010,359,800
leonard
02/02/2022 00:46:00
assuming youre on earth its 10
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504,278,422,521,118,700
kasperky
5519
kasperky
false
205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
193,942,262,336,454,660
KurtDee
02/02/2022 00:46:10
Okay now that everyone is here I’m leaving
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kasperky
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kasperky
false
205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:46:17
9.8 u mean
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help-1
f0d566dc2d184b829dd03a9e306eea74
649,984,702,010,359,800
leonard
02/02/2022 00:46:27
yeah
0
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help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:46:35
yeah but thats not the answer
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348,696,743,388,381,200
A Lonely Bean
7998
A Lonely Bean
false
205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:48:58
?
0
1
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help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:49:14
does any1 know??
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1
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help-1
f0d566dc2d184b829dd03a9e306eea74
872,024,354,572,103,700
<><><>
02/02/2022 00:50:43
What u wanna know
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help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:50:47
how to solve it
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1
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help-1
f0d566dc2d184b829dd03a9e306eea74
872,024,354,572,103,700
<><><>
02/02/2022 00:51:04
Do u know conversation of mechanical energy
0
1
null
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help-1
f0d566dc2d184b829dd03a9e306eea74
872,024,354,572,103,700
<><><>
02/02/2022 00:51:25
So the gravitational potential energy at the top = kinetic energy at bottom
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help-1
f0d566dc2d184b829dd03a9e306eea74
872,024,354,572,103,700
<><><>
02/02/2022 00:51:27
Soooo
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1
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help-1
f0d566dc2d184b829dd03a9e306eea74
872,024,354,572,103,700
<><><>
02/02/2022 00:51:39
$mgh = \frac{mv^2}{2}$
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help-1
f0d566dc2d184b829dd03a9e306eea74
510,789,298,321,096,700
TeXit
02/02/2022 00:51:43
**azeem321**
https://cdn.discordapp.c…354572103731.png
872024354572103731.png
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help-1
f0d566dc2d184b829dd03a9e306eea74
872,024,354,572,103,700
<><><>
02/02/2022 00:51:58
So
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help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:51:59
wait wait what
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1
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205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:52:06
so potential energy at the top
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205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:52:12
= to kinetic at the bottom
0
1
261,933,205,387,477,000
riemann
2529
riemann
false
205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
872,024,354,572,103,700
<><><>
02/02/2022 00:52:15
yh
0
1
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205,834
help-1
f0d566dc2d184b829dd03a9e306eea74
858,757,612,643,024,900
doggy
02/02/2022 00:52:23
ok then what is this
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