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|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
205,724 |
help-1
|
0c610917b4b4442b87682f0700204715
| 321,445,119,171,756,000 |
Shuri2060
|
01/29/2022 00:52:51
|
Not saying the answer will look nicer.
| 0 | 1 | null | null | null | null | null |
|||||
205,724 |
help-1
|
0c610917b4b4442b87682f0700204715
| 321,445,119,171,756,000 |
Shuri2060
|
01/29/2022 00:53:01
|
But I would see maybe
| 0 | 1 | null | null | null | null | null |
|||||
205,724 |
help-1
|
0c610917b4b4442b87682f0700204715
| 677,350,243,293,069,300 |
aab
|
01/29/2022 00:53:39
|
okay okay gotcha. thanks! .close
| 1 | 0 | null | null | null | null | null |
|||||
205,724 |
help-1
|
0c610917b4b4442b87682f0700204715
| 677,350,243,293,069,300 |
aab
|
01/29/2022 00:53:41
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:15:54
|
no clue on how to do this
|
unknown.png
| 1 | 0 | null | null | null | null | null |
||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:17:22
|
That means it's a right angled triangle
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:17:35
|
Draw the triangle and apply pythagoras theorem
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:19:32
|
to which sides?
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:20:43
|
No wait
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:21:00
|
Ooh yeah I've gotten it
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:21:09
|
Draw triangle ABC
| 0 | 1 | 935,204,719,972,974,700 |
HA2814
|
1529
|
HA2814
| false |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:21:33
|
Then drop a perpendicular line from A to BC
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:21:49
|
Then the meeting point is D
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:21:52
|
Solve...
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:22:26
|
so d should be between c and b
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:23:00
|
hmmmm but how do i extract an answer from this
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:23:24
|
nowhere does it state that cd is half of cb
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:23:56
|
It's at 90°
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:24:08
|
so is the answer 4.5?
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:24:57
|
Wait a sec
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:25:46
|
alright
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:28:31
|
Apply cosine rule
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:28:33
|
so do i literally just cut bc in half
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:28:41
|
haven't covered cosine before
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:28:51
|
No that's not right
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:29:01
|
not really sure where to go with this
| 1 | 0 | 825,545,259,194,515,500 |
Incipience
|
0159
|
Incipience
| false |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:36:32
|
Okay
| 0 | 1 | 825,545,259,194,515,500 |
Incipience
|
0159
|
Incipience
| false |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:36:47
|
Let me give you another method
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:38:01
|
Once you've drawn the triangle, Let AD be y and CD be x and use pythagorean theorem to find the eqns and solve them
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:40:14
|
Do you have the solution to this problem?
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:41:18
|
I'm pretty sure it's 4.5, but ive been wrong before
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:42:05
|
CD is undefined though
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:42:24
|
can't find the answer with only one variable
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:42:37
|
4.5 comes out as wrong
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:42:47
|
BD will be 9+x mind you
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:43:10
|
So you'll have to eqns for y
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:43:17
|
eqns?
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:43:27
|
Equations
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:44:29
|
i will try
| 1 | 0 | 353,581,489,201,348,600 |
RaceDaleJr88Fan
|
1107
|
RaceDaleJr88Fan
| false |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:44:38
|
gonna ask the teacher tomorrow if it doesn't make enough sense
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:44:46
|
The ans should be 25/6
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:45:36
|
Does D lie outside of the triangle?
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:46:37
|
Yes
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:47:12
|
If the angles were acute, would it just be 4.5?
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:47:49
|
My ACD was obtuse
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:48:30
|
Not really sure
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:50:20
|
wait how did you get this?
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:50:25
|
i put it in and it worked
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:51:25
|
Basically drew triangle ABC with angle ACD obtuse
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:51:56
|
So AD will be outside the triangle... to an extension of BC
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:52:52
|
Represented CD as x and AD as y
So basically BD will be 9+x
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:53:27
|
kinda makes sense
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:53:31
|
thank you for the help :)
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:53:53
|
Used pythagorean theorem to find the 2 eqns and solved them simultaneously
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:54:02
|
Welcome
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 01:55:06
|
this isn't perpendicular though
| 1 | 0 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:55:18
|
my drawing is horrible
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:55:49
|
This is correct
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:56:12
|
how would it look?
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:56:19
|
can you sketch for me?
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 914,473,169,648,255,000 |
skymoon
|
01/29/2022 01:58:09
|
20220129_095746.jpg
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:58:37
|
ohh
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 872,024,354,572,103,700 |
<><><>
|
01/29/2022 01:58:38
|
i see
| 0 | 1 | null | null | null | null | null |
|||||
205,725 |
help-1
|
86d78b7f860d40b38025beed8c0b81e8
| 541,081,246,252,531,700 |
nals
|
01/29/2022 02:10:21
|
it has been, thanks bros
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:17:06
|
IMG_0341.png
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:17:15
|
i don’t get why n has no effect on F(b) - F(a)
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:18:03
|
F(b), F(a) are integrals whose accuracies are affected by how big n is
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:18:11
|
by riemann sums, they have n partitions
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:19:13
|
see the first two lines and substitute that into the middle sum on the fourth line
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:19:42
|
taking limits
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:19:44
|
the way c_k is defined makes it not matter
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:20:49
|
wdym
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:23:08
|
c_k is defined such that <middle of the second line>
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:24:03
|
i’m concerned about n not affecting LHS
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:25:27
|
now i'm confused
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:25:34
|
which line are you having a problem with?
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:26:18
|
final
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:27:47
|
ah okay
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:28:38
|
the thing is, for each n, the c_k's change because your partitions change
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:28:44
|
yea
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:29:24
|
but the $c_k$'s are always defined so that the $\sum_{k=1}^n \dots$ is equal to $F(b) - F(a)$
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 510,789,298,321,096,700 |
TeXit
|
01/29/2022 02:29:27
|
**Camilleone**
|
569167697925898261.png
| 0 | 1 | null | null | null | null | null |
||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:30:03
|
we’re taking lim of n on both sides
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:30:06
|
and the limit of a constant sequence is just that constant
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:30:14
|
so won’t ie affect LHS in some way
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:31:03
|
no, because you're going $\lim \sum \dots = \lim (F(b) - F(a)) = F(b) - F(a)$
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 510,789,298,321,096,700 |
TeXit
|
01/29/2022 02:31:05
|
**Camilleone**
|
569167697925898261.png
| 0 | 1 | null | null | null | null | null |
||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:31:32
|
from the third last line
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:32:31
|
why lim (F(b) - F(a)) = F(b) - F(a)
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:33:06
|
limit of a constant sequence is that same constant
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:34:07
|
constant sequence?
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:35:20
|
a sequence $(a_k)$ is said to be constant if $\exists c$ such that $a_k = c$ for all $k$
for such a sequence, $\lim_k a_k = c$.
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 510,789,298,321,096,700 |
TeXit
|
01/29/2022 02:36:35
|
**Camilleone**
|
569167697925898261.png
| 0 | 1 | null | null | null | null | null |
||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 569,167,697,925,898,240 |
Camilleone
|
01/29/2022 02:36:43
|
sorry, i'm a bit out of it today, sick
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 261,933,205,387,477,000 |
riemann
|
01/29/2022 02:42:36
|
I think that was a good explanation, camil
| 0 | 1 | 748,636,086,816,866,400 |
!Flip.gg harshithimself
|
3587
|
!Flip.gg harshithimself
| false |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 261,933,205,387,477,000 |
riemann
|
01/29/2022 02:43:50
|
Just to add. It's like dividing up the interval [0, 1] into n parts.
| 0 | 1 | 456,226,577,798,135,800 |
Deleted User
|
0000
|
Deleted User
| false |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 261,933,205,387,477,000 |
riemann
|
01/29/2022 02:44:11
|
No matter how you divide up the interval, the lengths will always sum to 1
| 0 | 1 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:44:43
|
F(x) = int f(t) dt [a, x] here
| 1 | 0 | null | null | null | null | null |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 261,933,205,387,477,000 |
riemann
|
01/29/2022 02:45:21
|
Yea and the endpoints are [F(a), F(b)]
| 0 | 1 | 701,895,792,763,600,900 |
s_chanch
|
2633
|
s_chanch
| false |
|||||
205,726 |
help-1
|
41e26f76a25345bb9b35f8790cfe531a
| 701,895,792,763,600,900 |
s_chanch
|
01/29/2022 02:46:10
|
i still don’t get why taking the limit doesn’t affect LHS
| 1 | 0 | 456,226,577,798,135,800 |
Deleted User
|
0000
|
Deleted User
| false |
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